Math, asked by richardbarrett122603, 9 months ago

Solve the system of equations.

5y−4x=−7

2y+4x=14

y=
x=

Answers

Answered by kk2006gps
0

5y-4x= -7

5y= -7+4x

y= -7+4x/5

2y+4x=14

4x=14 - 2y

x=14 - 2y/4

I hope it is helpful

Answered by sahildhande987
220

\huge{\underline{\sf{\red{Answer}}}}

GIVEN:

Quadratic Equations

  • 5y-4x=-7

  • 2y+4x=14

SoluTion:

By Elimination Method

Multiplying (-1) in 1^st Equation

(-1)\times (5y-4x=-7)

\implies -5y+4x=7

Now,by applying the method

-5y+4x=7\\ \:+2y+4x=14 \\{\underline{-\:\: \: \: -\: \: \: \: \: \: \: \: \: -\: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \: \: }}  \\ -5y-2y +4x-4x = 7-14 \\ \\ -7y = -7

\boxed{y=1}

Now,

Value of x

Applying value of y in 1st Equation

5(1) -4x = -7

\implies -4x = -7 -5

\implies x =  \dfrac{\cancel{-12}}{\cancel{-4}}

\implies\large{\boxed{x=3}}}

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