Question

solve the system of equations are x+y+z=6;3x+3y+4z=20;2x+y+3z=13 using gauss jordan​

Answer 1

Answer:

step 1:

i made row 1 equal to row 1 multiplied by 3

i made row 3 equal to row 3 multiplied by 3

the result is shown in step 2.

step 2:

i made row 1 equal to row 2 minus row 2

i made row 3 equal to row 3 minus row 2

the result is shown in step 3.

step 3:

i made row 2 equal to row 2 multiplied by 5

i made row 3 equal to row 3 multiplied by 4

the result is shown in step 4.

step 4:

i made row 2 equal to row 2 minus row 3

the result is shown in step 5:

step 5:

i made row 3 equal to row 3 minus 20 * row 1

the result is shown in step 6.

step 6:

i made row 2 equal to 4 * row 2 minus row 3

the result is shown in step 7.

step 7:

i made row 2 equal to row 2 divided by 60

i made row 3 equal to row 3 divided by 12

the result is shown below:

step 8:

0 + 0 + 1 + 2

0 + 1 + 0 + 1

1 + 0 + 0 + 3

i flipped rows.

row 3 became row 1

row 1 became row 3

row 2 stayed where it was

the final matrix is shown below with the heading for each column on top

x + y + z + r

1 + 0 + 0 + 3

0 + 1 + 0 + 1

0 + 0 + 1 + 2

r is the result.

you get:

x = 3

y = 1

z = 2

Answer 2

Answer:

Step-by-step explanation: