Question

Solve the system of equations bx/a-ay/b+a+b=0
and bx-ay+2ab=0

Answer 1

Answer:

We have,

bx/a - ay/b+a+b=0......... (1)

And bx-ay+2ab = 0..........(2)

Dividing (2) by b and then substracting from (1) we get

bx/a-x + a+b-2a =0

=> (b-a)x/a + b - a =0

=> x = - a

Putting x in (2) we get

-ab - ay +2ab =0

=> y = b