Question

Solve the system of equations by Substitution OR elimination method:

3x + 2y = 41, 2x + 3y = 14​

Answer 1

Step-by-step explanation:

3x+2y=41........(I)

2x+3y=14........(ii)

Multiplying 3 in EQ (I) and 2 in eq (II)

We get,

9x+6y=123 ....(III)

4x+6y=28....(IV)

Subtracting these equations, we get

5x=95

x=95/5

x=13

substituting the value of x in eq (II) ,we get

2*13+3y=14

26 +3y=14

3y=12

y=4

so = x= 13

& y= 4