Math, asked by MB157232, 5 months ago

Solve the system of equations by using substitution. Show all work. List your answer as an ordered pair. 3x+2y=6 and 2/3y-x=6

Answers

Answered by ZZ0the0Queen
0

Answer:

Thx

Step-by-step explanation:

Answered by Anonymous
8

QUESTION:-

Solve the system of equations by using substitution.

SOLUTION:-

USING SUBSTITUTION METHOD:

(1)➥3x+2y=6

➠3x = 6 - 2y

➠x =  \frac{6 - 2y}{3}

(2)➥ \frac{2}{3y - x} =6

➠2 = 6(3y - x )

➠2 = 18y -6x

➠6x -18y = 2

➠6 ( \frac{6 - 2y}{3} ) - 18y = 2

 \frac{36 - 12y}{3} - 18y = 2

 \frac{36 - 12y - 54y}{3}  = 2

➠36 -66y = 6

➠66y = 36-6

➠y =  \frac{30}{66}

➠y =  \frac{5}{11}

sub/:- y =  \frac{5}{11} in (1)

➠3x+2y=6

➠3x+2 ( \frac{5}{11} ) = 6

➠3x + ( \frac{10}{11} ) = 6

 \frac{33x 10}{11} = 6

➠33x + 10 = 66

➠33x = 66-10

➠33x = 56

➠x = \frac{56}{33}

therefore ,

  • x =  \frac{56}{33}
  • y =  \frac{5}{11}

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USING ELIMINATION METHOD :

(1)3x+2y=6

(2)➜ \frac{2}{3y - x} =6

➠2 = 6(3y - x )

➠2 = 18y -6x

➠6x -18y = 2

by elimination method ,

(1)× 2 ➜6x + 4y = 12

(2) ➜6x -18y = 2

________________

➠22y = 10

➠y =  \frac{10}{22}

➠ y =  \frac{5}{11}

sub/:- y =  \frac{5}{11} in (1)

➠3x+2y=6

➠3x+2 ( \frac{5}{11} ) = 6

➠3x + ( \frac{10}{11} ) = 6

 \frac{33x  + 10}{11} = 6

➠33x + 10 = 66

➠33x = 66-10

➠33x = 56

➠x = \frac{56}{33}

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