Math, asked by Sadhvika35, 1 year ago

Solve the system of equations for a and

b.3( a+3b)=11ab, 3( 2a+b)=7ab

Answers

Answered by chotirani51
7
{3a+9b=11ab}×2-----1
6a+3b=7ab----2
dividing 2 from 1

6a+18b=22ab
6a+3b=7ab
-__-___-_____
0+15b=15ab
___________
a=1
6a+3b=7ab
6+3b=7b
3b-7b=-6
-4b=-6
b=3/2
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