Solve the system of equations using elimination.
4x + 6y = 16
x + 3y = 4
Answers
Answered by
2
by elimination method
4x + 6y =16
4(x+3y =4
4x +12y = 16
now using elimination method
4x+6y=16
4x+12y=16
- - -
0 -6y = 0
y = o/-6
y = 0 put the value in equation 1st
4x+6y=16
4x+6(0) = 16
4x+0=16
4x=16
x=16/4
x=4
y=0
4x + 6y =16
4(x+3y =4
4x +12y = 16
now using elimination method
4x+6y=16
4x+12y=16
- - -
0 -6y = 0
y = o/-6
y = 0 put the value in equation 1st
4x+6y=16
4x+6(0) = 16
4x+0=16
4x=16
x=16/4
x=4
y=0
Answered by
1
The solution is x = 4 and y = 0
Solution:
Given system of equations are:
4x + 6y = 16 ---------- eqn 1
x + 3y = 4 ------- eqn 2
We have to solve the equations
Multiply eqn 2 by -4
-4x - 12y = -16 ------- eqn 3
Add eqn 1 and eqn 3
4x + 6y = 16
-4x - 12y = -16
( + ) ---------------
-6y = 0
y = 0
Substitute y = 0 in eqn 2
x + 3(0) = 4
x = 4
Thus solution is x = 4 and y = 0
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