Question

Solve the system of equations

-x/2 + y/3 = 0

x + 6y = 16

Answer 1

Solutions 

We first multiply all terms of the first equation by the LCM of 2 and 3 which is 6. 

6(-x/2 + y/3) = 6(0) 

x + 6y = 16 

We then solve the following equivalent system of equations. 

-3x + 2y = 0 

x + 6y = 16 

which gives the solution 

x = 8/5 and y = 12/5

Answer 2

For solving the system of equations : 

(i) $\frac{-x}{2}$ + $\frac{y}{3}$ = 0 

(now for further more steps we need to do addition for that we need to find out the LCM of the denominator)

⇒ the LCM of 2 and 3 is "6" 

(now again we will multiply the equation 1 with 6)

⇒  6×{$\frac{-x}{2}$ + $\frac{y}{3}$} = {6}0 

 x+6y=16 

 (NOW BY SOLVING THE EQUIVALENT SYSTEM OF EQUATION)

with "-3x + 2y = 0" and "x + 6y = 16" 

By doing the solutions the answers would : 

⇒ x = $\frac{8}{5}$

⇒ y = $\frac{12}{5}$

∴ x = $\frac{8}{5}$ 

∴ y = $\frac{12}{5}$