Question

Solve the system of equations
-x/2 + y/3 = 0

x + 6y = 16

Answer 1

Solutions 

We first multiply all terms of the first equation by the LCM of 2 and 3 which is 6. 

6(-x/2 + y/3) = 6(0) 

x + 6y = 16 

We then solve the following equivalent system of equations. 

-3x + 2y = 0 

x + 6y = 16 

which gives the solution 

x = 8/5 and y = 12/5

Answer 2

multiply first equation by 6

6(-x/2 + y/3) = 6(0) 
-3x + 2y =0 ------------------- 1

x + 6y = 16 

x = 16 - 6y ----------------------2

substitute 2 in 1

-3(16 -6y ) + 2y = 0
-48 y + 18 y + 2y =0
-48 + 20y =0

48/20=y

12/5 =y                                                                                   

substiute y in 2

x + 6(12/5) = 16

x = 8/5