Math, asked by prakher694, 8 months ago

Solve the system of equations x+3y+z=13,3x+y+z=11,x+y-3z=11

Answers

Answered by mustufapatva
0

Answer:

Step-by-step explanation:

given that,

x + 3y + z = 13 ----1

3x + y + z = 11 ----2

by 2 - 1,

2x - 2y = -2 -----3

x + y - 3z = 11 ----4

by 4 - 3 ,

-x -3y - 3z = -13

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