Math, asked by KINGANANT, 11 months ago

Solve the system of equations x/a+y/b=a+b , x/a2+y/b2=2​

Answers

Answered by lipsa91245
2

x/a + y/b= a+b

=>xb+ya=a^2b+ab^2----------(1)

x/a^2 +y/b^2 =2

xb^2+ya^2=2a^2b^2------------(2)

(1)xb=xb^2+yab=a^2b^2+ab^3

(2)x1=xb^2+ya^2=2a^2b^2

substrate (2)from(1)

we get....

=>yab-ya^2=ab^3-a^2b^2

=>ya(b-a) =ab^2(b-a)

=>y=b^2

puting this in equation (2)we get

=>x=a^2

I think this will help you


KINGANANT: can you please show me the subtraction between both of them .
KINGANANT: I am not able to understand how you got yab- ya2=ab3- a2b2
KINGANANT: please
KINGANANT: if you will give my answer, I will mark you as brainlist
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