Question

solve the system of equations: y=3x y=x^2-4

Answer 1

$\huge\mathfrak\pink{Heya User}$

⚫y=3x...(1)

↪y=x^2-4...(2)

putting up the value of'y' in EQ 2

We get,

✔3x=x^2-4

✔x^2-3x-4

✔x^2-4x+x-4

✔x(x-4)+1(x-4)

✔(x+1)(x-4)are the factors ❗

VALUE OF'X'IS;

X=-1,4(PUT THIS VALUE IN EQ1)

SO,

⭕Y=3(-1)

Y=-3

⭕Y=3(4)

Y=12

VALUE OF'Y'IS;

⚫-3,12

HOPE IT MAY HELPS UH ❤✌

Answer 2

$\huge\mathfrak\red{Hi}$

⚫X=-1,4

⚫Y=-3,12

Solution is given by 1 usr✌✌