Math, asked by maurkeria02, 10 months ago

Solve the system of equations: y = x2 + 2x – 3 and y = 3x + 3

Answers

Answered by bikramjitsarker28
0

Step-by-step explanation:

given that y=x2 +2x -3

and y=3x + 3

then,

x2 +2x -3 = 3x+ 3

=x2 +2x-3 -3x -3=0

=x2 -x -6

= x2 +2x -3x -6

=x(x+2)-3(x+2)

=(x+2)(x-3)

x=-2

then y= 3×(-2)+ 3= -3

x= 3

then y= 3×3+3=9

hope you will be helped

mark as brainliest plz

Answered by ljpanandbabu
0

Answer:

y=x2+2x-3=x2+3x-x-3=x(x+3)-1(x+3)=(x-1)(x+3) now y=3*3+3=12

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