solve the system of linear equation 2x+3y=12 and x-2y=-1
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Given linear equation are
2x+3y=12.......i and
x-2y=-1......ii
multiplying eqn ii by 2 we get
2x-4y=-2.......iii
Subracting eqn i from ii
2x+3y=12
2x-4y=-2
- + +
7y = 14
so y = 2
substituting value of y in eqn ii
x-2y=-1
or x-2.2 = -1
so x = 3
therefore x=3 and y=2
hope it helps uu
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