Question

solve the system of linear equation by cramers rule x+2y=3,2x+4y=8​

Answer 1

$\textbf{Given:}$

$\textsf{Equations are}$

$\mathsf{x+2y=3\;and\;2x+4y=8}$

$\textbf{To find:}$

$\textsf{Solution of the given system by cramer's rule}$

$\textbf{Solution:}$

$\mathsf{\triangle=\left|\begin{array}{cc}1&2\\2&4\end{array}\right|}$

$\mathsf{\triangle=4-4=0}$

$\mathsf{{\triangle}_x=\left|\begin{array}{cc}3&2\\8&4\end{array}\right|}$

$\mathsf{{\triangle}_x=12-16=-4\;\neq\;0}$

$\therefore\textsf{The given system of equation has solution}$

$\textbf{Find more:}$

Find x,y,z using cramers rule, if x-y+z=4, 2x+y-3z=0 and x+y+z=2

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By Using cramer's rule solve the given linear equations.

x + y-Z=1; 8x + 3y - 6Z=1; 4x - y +3Z =1​

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