Solve the system of linear equation by substitution.
b = -3a - 7
b = a + 9
Solution: (☐, ☐)
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Answered by
1
-3a+b=-7
b=a+9
By substituting value of b=a+9 in - 3a+b=-7
-3a+a+9=-7
-2a=-16
a=8
b=17
reema593:
Wrong answer
Answered by
7
Let's start by solving for a.
Take the first equation, b = -3a - 7, and substitute in the second equation, b = a + 9, for b.
We now have:
a+ 9 = -3a - 7
Add 3a to both sides.
4a + 9 = -7
Subtract 9 from both sides.
4a = -16
Divide each side by 4.
a = -4
Let's use the second equation, b = a + 9, to solve for a.
Put in the value we just solved for.
We now have:
b = -4 + 9
Simplify.
b = 5
Let's check our answer, starting with the first equation, b = -3a - 7.
Put in the values for a and b.
5 = -3(-4) - 7
5 = 12 - 7
5 = 5
Do the same with the second equation, b = a + 9.
5 = -4 + 9
5 = 5
The solution to the system of equations is (5, -4).
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