Question

Solve the system of linear equation by the cross multiplication method 3x+y-13=0 and x-3y+9=0

Answer 1

Step-by-step explanation:

A1=3,B1=1,C1=-13. A2=1,B2=-3,C2=9

by cross multiplication method

x/(B1*C2-B2*C1)=Y/(C1*A2-C2*A1)=1/(A1*B2-A2*B1)

x/{(1*9)-(-3*-13)}=y/{(-13*1)-(9*3)}=1/{(3*-3)-(1*1)}

x/(9-39)=y/(-13-27)=1/(-9-1)

x/(-30)=y/(-40)=1/(-10)

solving separately to get the value of x and y

for x,

x/(-30)=1/(-10)

x=(-30)/(-10)

x=3

for y,

y/(-40)=1/(-10)

y=(-40)/(-10)

y=4