Question

solve the system of linear equations using substitution method

Answer 1

Answer:

$y = 2x - 1 \: \: \: \: and \: \: \: \: y = x - 8$

put y = x-8 in 1st equation

$y = 2x - 1 \\ x - 8 = 2x - 1 \\ x = - 7$

put x = -7 in 2nd equation

$y = x - 8 \\ y = - 7 - 8 = - 15$