Question

Solve the system of simultaneous linear equations by substitution method: 3+(x-5)=y+2, 2(x+y)=4-3y​

Answer 1

Answer:

$answer \\ - 3 - (x - 5) = y + 2 \\ 2(x + 2) = 4 - 3y$

Now the further solving

1.

$- 3 - x + 5 = y + 2 \\ x + y + 2 = 2 \\ x - y = 0$

2.

$2x + 2 = 4 - 3y \\ 2x - y = 4 \\ 2x - y = 4$

Now subtracting 1 from 2

$2x - y = 4 \\ - x + y = 0$

________________

$x = 4$

Now from equation

$x - y = 0 \\ x = y \\ 4 = y \\ y = 4 \\ hence \\ x = 4 \\ y = 4$

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