Question

Solve the system using the elimination method. Write the solution as an ordered pair. 3x + 2y = 3 2x + 3y = 2

Answer 1

Answer:

x=1

y=0

Step-by-step explanation:

3x+2y=3.......(i)

2x+3y=2.......(ii)

From (i) no equation,

x+2/3y=1

From (i),

x+3/2y=1

Subtracting this new two equation,

(2/3-3/2)y=0

y=0

x=1(put the value of y in any eqn)

Answer 2

Step-by-step explanation:

We have,

3x + 2y = 3 ----- 1

2x + 3y = 2 ----- 2

Multiplying the whole eq.1 with 2 and eq.2 with 3 we get,

6x + 4y = 6 ---- 3

6x + 9y = 6 ----- 4

Using elimination method,

Subtracting eq.3 from eq.4 we get,

(6x + 9y) - (6x + 4y) = 6 - 6

6x + 9y - 6x - 4y = 0

5y = 0

y = (0/5)

y = 0

Putting y = 0 in eq.1 we get,

3x + 2(0) = 3

3x = 3

x = 3/3

x = 1

Hence,

x = 1 and y = 0

Hope it helped and believing you understood it........All the best