Question

Solve: The teacher divided a class of 48 students into five groups for different activities for the class exhibition. The second group was 5 students less than the first group. The fifth group was equal to the second group. The third group was 2 students more than the fourth group. The fourth group was 3 students more than the fifth group.What are the number of students in each group?

Answer 1

Let the first group students be x

Then second group is x-5

now fifth group is x-5

then forth group is (x-5)+3

now third group is [(x-5)+3]+2

now

the total sum is 48

thus

x+x-5+x-5+(x-5)+3+[(x-5)+3]+2 = 48

now solve and get the answer

Answer 2

Answer:

let it of first group student be x . the second group is X - 5. now v group is X - 5. IV group is (x-5)+3 now third group is [(x-5)+3]+2 now the total sum is 48 thus. x+x-5+x-5+(x-5)+3+[(x-5)+3]+2_48