Question

solve the this question​

Answer 1

Answer ⬇️

Given -

a + b = 10 and ab = 6

The quadrilatic polynomial whose zeroes are a , b is ,

f ( x ) = k [ x² - ( a + b )x + ab ]

= k [ x² - 10x + 6]

When 'k' is any non zero real number

Answer 2

Answer:

The quadratic polynomial be x^2 - 10x +6.

Step-by-step explanation:

Let,the quadratic polynomial be ax^2 + bx + c = 0.

Now,

α + β = 10 = -b/a

αβ = 6 = c/a

Here, a=1, b= (-10) and c=6.

So, by substituting the value of a,b and c in ax^2 +bx+c =0, we get

x^2 - 10x + 6 = 0.