Question

solve the this question​

Answer 1

Answer:

dj alok

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Answer 2

Answer:

∠ATO = 40° …given From T we have two tangents TA and TB We know that if we join point T and centre of circle O then the line TO divides the angle between tangents ⇒ ∠ATO = ∠OTB = 40° …(i) ∠OAT = ∠OBT = 90° …radius is perpendicular to tangent …(ii) Consider quadrilateral OATB ⇒ ∠OAT + ∠ATB + ∠TBO + ∠AOB = 360°…sum of angles of quadrilateral From figure ∠ATB = ∠ATO + ∠OTB ⇒ ∠OAT + ∠ATO + ∠OTB + ∠TBO + ∠AOB = 360° Using (i) and (ii) ⇒ 90° + 40° + 40° + 90° + ∠AOB = 360° ⇒ 260° + ∠AOB = 360° ⇒ ∠AOB = 100°Read more on Sarthaks.com - https://www.sarthaks.com/964227/in-the-given-figure-if-ato-40-find-aob