Math, asked by gokgxg, 1 year ago

Solve the triangle in which a=√3+1, b=√3-1 and c=60°

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Answered by Anonymous
5
Solution: Let A = 60o ⇒ B + C = 120o. Also tan (B – C)/ 2 = (b – c)/(b + c) cot A/2. = (√3 + 1 - √3 + 1) / (√3 + 1 + √3 – 1) cot 30o. = 1. ⇒ (B – C)/2 = 45o. ⇒ B – C = 90o. ⇒ B ... after this solve it's own and hop its helpful
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