Math, asked by ibrahim59, 11 months ago

Solve the triangle in whicha=2, b=1 and c=13.​

Answers

Answered by Anshimish0105
1

s=(a+b+c)/2

(2+1+13)/2

16/2=8

area of triangle

 \sqrt{s(s - a)(s - b)(s - c)}

 \sqrt{16(16 - 2)(16 - 1)(16 - 13)}  \\  \sqrt{16 \times 14 \times 15 \times 3}  \\  \sqrt{10080 } \\ 100.39cm ^{2}

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