Math, asked by jungkooksbread, 20 days ago

Solve the trigonometry equation

Sin(x + 30°) = 4/10 where -180° ≤ x ≤ 180°

Answers

Answered by biswajit0070
0

Answer:

I don't know sorry buddy.

Answered by saathviks78
1

Answer:

Sin ( A + B ) = Sin A Cos B + Cos A Sin B

i.e ,

Sin ( x + 30° )

=> Sin x Cos 30° + Cos x Sin 30 ° = 4 /10

=> Sin x × √3 / 2 + Cos x × 1/2 = 4 / 10

=> 1 / 2 { √ 3 Sin x + Cos x } = 4 / 10

=> √ 3 Sin x + Cos x = 4 / 5

=> If Value of 4 / 5 or 4 /10 is given

Then , It can be Solved .

Similar questions