Question

Solve the value for x and y =?
(a-b)x+(a+b)y=a²-2ab+b²
(a+b)(x+y)=a²-b²
Please answer in good content
wrong answer will be deleted at the spot.​


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Answer 1

Answer:

(a-b) x + (a + b) y = a² - 2ab - b²…………(1)

(a + b) (x + y) = a² + b²……………………(2)

Equation (2) can be written as (a + b)x+ (a+b) y = a² + b²………….(3)

Now we have to solve equation (1) and (3)

(a-b) x + (a + b) y = a² - 2ab - b²,…………(1)

(a + b)x+ (a+b) y = a² + b²………….(3)

Subtracting equation (3) from (1) we get

(a-b-a-b) x = a² - 2ab - b²- a² - b²

-2b x = - 2ab -2 b²

-2b x =-2b(a+b)

dividing both sides by -2b

x = a+b

Now substitude x=a+b in equation (1) we get

(a-b)(a+b) + (a + b) y = a² - 2ab - b²

a² - b² + + (a + b) y = a² - 2ab - b²

Subtracting a² - b² from both the sides

(a + b) y = a² - 2ab - b² - a² + b²

(a + b) y = - 2ab

y = - 2ab /(a+b)

Answer x = a+b , y = - 2ab /(a+b)

Answer 2

1. (a-b) x + (a + b) y = a² - 2ab - b²…………(1)

(a + b) (x + y) = a² + b²……………………(2)

Equation (2) can be written as (a + b)x+ (a+b) y = a² + b²………….(3)

Now we have to solve equation (1) and (3)

(a-b) x + (a + b) y = a² - 2ab - b²,…………(1)

(a + b)x+ (a+b) y = a² + b²………….(3)

Subtracting equation (3) from (1) we get

(a-b-a-b) x = a² - 2ab - b²- a² - b²

-2b x = - 2ab -2 b²

-2b x =-2b(a+b)

dividing both sides by -2b

x = a+b

Now substitude x=a+b in equation (1) we get

(a-b)(a+b) + (a + b) y = a² - 2ab - b²

a² - b² + + (a + b) y = a² - 2ab - b²

Subtracting a² - b² from both the sides

(a + b) y = a² - 2ab - b² - a² + b²

(a + b) y = - 2ab

y = - 2ab /(a+b)

Answer x = a+b , y = - 2ab /(a+b)

hope it helps you !!!!

I hv tried to solve it !!!☺️