Question

Solve the value of x and y
x + 4y = 27xy—— 1
x + 2y = 21xy—— 2​

Answer 1

Step-by-step explanation:

X+4y=27xy (1)

x+2y=21xy (2)

divide both the equation by xy

(x+4y =27xy)/xy

x/xy+4y/xy =27xy/xy

1/y+4/x =27

1(1/y)+4(1/x)=27

substitute

p = 1/x

q =1/y

p+4q =27 (3)

- p+2q =21 (4)

-----------------------

2q = 6

q =6/2

=3

now ,substitute q's value in equation (4)

p+2q =21

p+2 * 3 = 21

p + 6 =21

p =21-6

=15

therefore

we know that

q= 1/y

1/y =1/3

p =1/x

1/x = 1/15

Answer 2

Answer:

subtracting equation 2 from 1

x+4y=27xy

- x-2y=-21xy

2y=6xy

6x=2. [ y on both sides gets cancelled]

x=1/3

substituting the value of x in equation 1

(1/3)+4y=27(1/3)y

1/3+4y=9y

LCM of 3 and 1 =3

1+12y=27y

15y=1

y=1/15

Hope it helps