Math, asked by dahibhat9, 4 days ago

Solve the venn diagram question based on the data given. Two sets A & B intersect in such a way that, Ratio of Number of elements in only A to only B = 1:8 Ratio of Number of elements common to both A & B to only B = 1:4. Number of elements that belong to neither A or B is zero. Based on the data, the possible value for number of elements in AUB, can be,
98
140
112
132​

Answers

Answered by amitnrw
2

Given :  Two sets A & B intersect in such a way that, Ratio of Number of elements in only A to only B = 1:8

Ratio of Number of elements common to both A & B to only B = 1:4.

Number of elements that belong to neither A or B is zero.  

To find :  the possible value for number of elements in AUB

Solution:

Only A  =  n(A) -  n(A ∩ B)

only B  =  n(B)  -  n(A ∩ B)

Ratio of Number of elements in only A to only B = 1:8

=> ( n(A) -  n(A ∩ B)) / (n(B)  -  n(A ∩ B)) = 1/8

=> 8 n(A) - 8 n(A ∩ B) = n(B)  -  n(A ∩ B)

=> 8 n(A) = n(B) +  7n(A ∩ B)

n(A ∩ B) / ( n(B)  -  n(A ∩ B) ) = 1/4

=> 4 n(A ∩ B) = n(B)  -  n(A ∩ B)

=>  n(B) = 5n(A ∩ B)

8 n(A) = n(B) +  7n(A ∩ B)

=> 8 n(A) = 5n(A ∩ B) +  7n(A ∩ B)

=>  n(A) =  1.5n(A ∩ B)

n(AUB) = n(A) + n(B)  - n(A ∩ B)  

=> n(AUB)= 1.5n(A ∩ B)  +5n(A ∩ B)  - n(A ∩ B)  

=> n(AUB) = 5.5n(A ∩ B)

132/5.5  = 24  given only  integral value

Rest 98/5.5 , 140/5.5  and 112/5.5  Does not give integral value

Hence 132  is , the possible value for number of elements in AUB

n(A ∩ B) = 24

n(A) = 36   only A = 12

n(B) = 120  only B  = 96

132 is the correct answer.

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Answered by RvChaudharY50
3

Solution :-

given that,

→ only A : only B = 1 : 8

→ A∩B : only B = 1 : 4 = 2 : 8

so,

→ only A : A∩B : only B = 1 : 2 : 8

then,

→ |AUB| = |onlyA| + |A∩B| + |onlyB|

Now, let x = |onlyA|

so,

→ |AUB| = x + 2x + 8x = 11x

since , x is a natural number , |A∪B| must be a multiple of 11 .

checking options we get,

→ 132/11 = 12 quotient and 0 remainder .

hence, the possible value for number of elements in AUB is 132 .

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