Math, asked by shravnitaranekar, 6 months ago

SOLVE THE WHOLE QUESTION. ​

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Answers

Answered by diksha30508
0

Answer:

sorry I don't know

Step-by-step explanation:

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Answered by dhruvsh
4

Answer:

x/y + y/x = -1

=> x^2+ y^2/xy = -1

or,

x^2+y^2 + xy=0

Now,

x^3-y^3 = (x-y)(x^2+xy+y^2) = (x-y)(0) = 0

Therefore, x^3-y^3 = 0

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