Question

solve the word problem by using simultaneous linear equation

1. The sum of an uncle's and his nephew's ages is
46. Three years hence the uncle will be 3 times the
nephew's age. Find their present ages.​

Answer 1

Answer:let the age of the uncle be x yrs

and the nephew be y yrs

then,

x+y=46....eqn(i)

now,

after 3yrs nephews' age=y+3

and

uncle = x+3

so,

3(y+3)= (3+x)

or,

x+3= 9+3y

or,

x-3y=9-3

or,

x-3y= 6.....eqn(ii)

so,

substracting eqn (ii) from (i),we get,

4y= 40

or,

y=10

thus,

putting the value of x in eqn (i), we get,

x+10=46

or,

x=36

therefore,

the present age of the uncle is 36yrs

and the nephew is 10yrs

Step-by-step explanation:

Answer 2

Step-by-step explanation:

1. let uncle's age is X and nephew's age isY.
2. sum of their ages is 46
3. X+Y=46
4. after 3 years.
5. uncle's age will became X+3.
6. and nephew's age became Y+3.
7. acc. to question X+3=3(Y+3)
8. now solve it.
9. it is easy now.