solve the|x-1|+|x-2|≥3
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Answer:
the given equation is |x-1|+|x-2|≥3
Step-by-step explanation:
according to its limits, if the given limits to it lie between 0 and ∞, then the mod function is positive and negative if it lies b/w o and-∞.
- for +∞
x-1+x-2≥3
2x-3 ≥3
after solving we have x≥ 9/2
- for-∞
-x+1-x+2≥3
-2x+3≥3
2x-3≤3
therefore x≤9/2
thus the limits of x are . -9/2 ≤ x ≥ 9/2
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