Solve the x²-2 (a+2)x+(a+1)(a+3)=0
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Answer:
x = a+3 and x = a+1
Step-by-step explanation:
x² - 2(a+2) x + (a+1)(a+3) = 0
We know that
A = 1
B = -2(a+2)
C = (a+1) (a+3)
D = B² - 4AC
= 4(a+2)² - 4(a+1)(a+3)
= 4 [a² + 4 + 4a - a² - 4a - 3]
D = 4>0
Now we will use the quadratic formula and we will get this:
x = -B + √D/2A and x = -B - √D/2A
x = 2(a+2)+2/2 and x = 2(a+2)-2/2
x = a+3 and x = a+1
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