Math, asked by ranideviddcip, 2 months ago

Solve the x²-2 (a+2)x+(a+1)(a+3)=0​

Answers

Answered by eraams
1

Answer:

x = a+3 and x = a+1

Step-by-step explanation:

x² - 2(a+2) x + (a+1)(a+3) = 0

We know that

A = 1

B = -2(a+2)

C = (a+1) (a+3)

D = B² - 4AC

= 4(a+2)² - 4(a+1)(a+3)

= 4 [a² + 4 + 4a - a² - 4a - 3]

D = 4>0

Now we will use the quadratic formula and we will get this:

x = -B + √D/2A and x = -B - √D/2A

x = 2(a+2)+2/2 and x = 2(a+2)-2/2

x = a+3 and x = a+1

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