solve the yč of D²(D²+4)=96x²+sin2x-k
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Answer:
f(D)=D⁴+4D²
A.F,f(m)=0
m⁴+4m²=0
m²(m²+4)=0
m²=-4
m=2i,-2i
so,m=0,0,2i,-2i
therefore,
yc=(c1+c2x)e^0x+e^0x(c3cos2x+c4sin2x)
=(c1+c2x)+c3cos2x+c4sin2x.
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