solve the y3+x3 dy/dx=0
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x2ydx−(x3+y3)dy=0dydx=x2yx3+y3
Putting x=vy
dydx=v+ydydvdydx=x2yx3+y3⇒v+ydydv=v2y3v3y3+y3=v2v3+1ydydv=v2v3+1−
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3x^2
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