solve thease 27x³+y³=.
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27x³+y³
(3x)³+(y)³
(3x+y)[(3x)²-3x×y+(y)²]
(3x+y)(9x²-3xy+y²)
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Step-by-step explanation:
See the attachment
identity used
a^3 + b^3 =(a+b)(a^2 - ab +b^2)
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