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4. Area of circle = pi r^2
so semicircular region ==> pir^2 /2
==> 22/7 x 14 x 14 x 1/2
==> 22 x 14 ==> 308 cm square
5. Split the figure into one rectangle and two semicircles
Area of rectangle
l = 36-7-7 = 36-14 = 22
b = 14
lb ==> 22x14 ==> 308
Area of 2 semicircle = area of one circle
pi r squared ==> 7 x 22/7 x 7 ==> 154
total area = 154+308 ==> 462
6. Area of ABCD = area of parallelogram ==> bh
take height = y and CD = base = 31 cm
area = 31 x y
given area = 155
therefore y = 155/31 = 5 cm //
so semicircular region ==> pir^2 /2
==> 22/7 x 14 x 14 x 1/2
==> 22 x 14 ==> 308 cm square
5. Split the figure into one rectangle and two semicircles
Area of rectangle
l = 36-7-7 = 36-14 = 22
b = 14
lb ==> 22x14 ==> 308
Area of 2 semicircle = area of one circle
pi r squared ==> 7 x 22/7 x 7 ==> 154
total area = 154+308 ==> 462
6. Area of ABCD = area of parallelogram ==> bh
take height = y and CD = base = 31 cm
area = 31 x y
given area = 155
therefore y = 155/31 = 5 cm //
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