Solve these-
1)Two numbers are in the ratio 5:3.If they differ by 18,what are the two numbers?
2)A number is decreased by 5% of it is 3800.What is the number?
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Answers
Answered by
369
let the 2 numbers be 5x and 3x.
5x-3x = 18
2x = 18
x = 18/2
x= 9
therefore the first number = 5 *9
= 45
the second number = 3*9
= 27
percentage of decrease = 5 %
the original number = (5/100)*3800
= 3800 - 190
= 3610
5x-3x = 18
2x = 18
x = 18/2
x= 9
therefore the first number = 5 *9
= 45
the second number = 3*9
= 27
percentage of decrease = 5 %
the original number = (5/100)*3800
= 3800 - 190
= 3610
Answered by
104
if two numbers are in the ratio 5:3 , it means the total of the two is 8 parts and the two numbers are 5 parts and 3 parts of the total.
Then the difference between them is 2 parts of the total. Two parts are equal to 18. So one part is 9. So eight parts will then be 8*9 = 72. Then the two numbers are 5 parts = 5*9=45 and three parts 3*9 = 27.
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If a number is decreased by 5%, then it becomes 100 % - 5% = 95% of itself.
That means 95/100 of number is 3, 800.
The number then will be equal to 3,800 * 100 /95 = 4, 000
Then the difference between them is 2 parts of the total. Two parts are equal to 18. So one part is 9. So eight parts will then be 8*9 = 72. Then the two numbers are 5 parts = 5*9=45 and three parts 3*9 = 27.
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If a number is decreased by 5%, then it becomes 100 % - 5% = 95% of itself.
That means 95/100 of number is 3, 800.
The number then will be equal to 3,800 * 100 /95 = 4, 000
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