Question

solve these
1.x to the power 4+4.
2. x to power 4 -1.
3.x to the power 4+ x to power 2+1

Answer 1

1 ) x^4 + 4 =0

x^4 = -4
we see LHS is positive term but RHS is negative term
so here real solution is not possible .

2) x^4 -1 =0
(x^2+1)(x^2-1)=0

here x^2 + 1 ≠0

(x -1)(x +1)=0
x = 1 , -1
so, answer is -1 and 1

3) x^4 +x^2 +1 =0
let x^2 =t

t^2 + t +1 =0

find Discrimannt =1 -4 <0
so, no real solution possible

Answer 2

Answer:jfcgvfhghcvfjgv

Step-by-step explanation: