Question

solve these 2 questions​

Answer 1

Answer:

17. pr is a straight line

(3x+10)+(7x-30)=180° =>linear pair

10x - 20 = 180°

10x =180+20

x=200/10

x=20°

(3x+10)=3(20)+10

=70°

7x-30=7(20)-30

=110°

18. AOB+BOC =180° (LINEAR PAIR)

x+2x=180°

3x=180°

x=180°/3

x=60

substitute the values

Answer 2

Answer:

angle POQ=110°

Step-by-step explanation:

as we know that angle on straight line =180°

so,

(3x+10)°+(7x-30)°=180

7x-30+3x+10=180

10x-20=180

10x=180+20

10x=200

x=200/10

x=20

so ∠POQ=7x-30

               =7(20)-30

               =140-30

               =110