Question

solve these 2 questions as early and neatly ad possible pls

Answer 1

Ans-9) (i) Radius of cylindrical tank (r)=(4.2/2) m= 2.1m
Height (h)=4.5m
Curved Surface Area (CSA)= 2×pie×r×h
=(2×22/7×2.1×4.5)m2
=(2×22×0.3×4.5) m2= 59.4m2

Total Surface Area (TSA) of tank=2×22/7×r (r+h)
=[(2×22/7×2.1)(2.1+4.5)]m2
=(44×0.3×6.6)m2
=87.12m2
(ii) Let A m2 steel sheet be actually used in making the tank.
> A (1-1/12)=87.12m2
> A= (12/1×87.12) m2
> A= 95.04m2
Therefore, 95.04m2 steel was used in actual while making such a tank.

Ans-10 Height(h) of lampshade= (2.5+2.5+30) cm=35cm
Radius(r) of the circular end of the frame of lampshade=(20/2) cm=10cm
Cloth required for covering the lampshade= Curved Surface Area (CSA) of lampshade
=2×pie×r×h
=(2×22/7×10×35)cm2
=(50×44)cm2
=2200cm2
Please give me thanks and make my answer the brainliest answer.