Math, asked by gungun010203, 7 months ago

solve these 2 questions with full explanation step by step​

Attachments:

Answers

Answered by burnwalsneha187
1

Answer:

3x^2- 2 root 6 x +2=0

Step-by-step explanation:

3x^2-(root 6 + root 6)x +2=0

3x^2-root 6 x -root 6 x+2=0

we can write 3= root 3 × root 3

similarly 2= root 2 ×root 2

so,

=>(root 3× root 3 x^2-root 6x) -(root 6x +root 2× root 2 )=0

=>root 3 x (root 3 x - root 2)- root 2 (root 3 x-root2 )=0

=>(root 3x- root 2)(root 3x-root 2)=0

x=root 2/3 answer

Similar questions