solve these all three questions
please its urgent
i will mark him or her brainilist for sure
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9. x-1=cuberootof 8
x-1=2
x=3
so (x+1)^2=(3+1)^2
16
10. 2^4 * 4^2=16^x
4^2*4^2=16^x
4^4=16^x
16^2=16^x
x=2
11. if 3^x-1=9
3^x-1=3^2
x=3
if 4^y+2=64
4^y+2=4^3
y=1
so x/y=3/1
x-1=2
x=3
so (x+1)^2=(3+1)^2
16
10. 2^4 * 4^2=16^x
4^2*4^2=16^x
4^4=16^x
16^2=16^x
x=2
11. if 3^x-1=9
3^x-1=3^2
x=3
if 4^y+2=64
4^y+2=4^3
y=1
so x/y=3/1
dilipkumarprinp4e6xm:
please mark brainliest
Answered by
0
1. (x-1)³=8
>> x-1=³√8
>>x-1=2
>>x=3
(x+1)1=(3+1)1=4²=16
2. 2⁴× 4² = 16^x
>> 2⁴ × 2²*² = 2^(4x)
a to the power b multiplied by a to the power c is a to the power of sum of b and c
L.H.S = 2^(4+4) = 2^8
R.H.S. = 2^(4x)
Equating,
2^8 = 2^(4x)
Remove the same base,
8=4x
x=2
3. 3^(x-1) = 3²
Remove base,
x-1=2
x=3
4^(y+2)=4³
remove the base
y+2=3
y=1
x/y = 3/1 = 3
#EffDaQuestioner
>> x-1=³√8
>>x-1=2
>>x=3
(x+1)1=(3+1)1=4²=16
2. 2⁴× 4² = 16^x
>> 2⁴ × 2²*² = 2^(4x)
a to the power b multiplied by a to the power c is a to the power of sum of b and c
L.H.S = 2^(4+4) = 2^8
R.H.S. = 2^(4x)
Equating,
2^8 = 2^(4x)
Remove the same base,
8=4x
x=2
3. 3^(x-1) = 3²
Remove base,
x-1=2
x=3
4^(y+2)=4³
remove the base
y+2=3
y=1
x/y = 3/1 = 3
#EffDaQuestioner
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