SOLVE
These both using BODMAS
1.QUESTION
-7+2x(-3) + 3-(-10)-48÷6
2. 100X(-10) + [400-{100-(50-5x10)}}
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answer of no. 1 question is -8
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Answer:
1) -7+2×(-3)+3-(-10)-48÷6
= -7-6+3+10-8
= -8
2) 100×(-10)+[400-{100-(50-5×10)}]
=-1000+[400-{100-(50-50)}]
=-1000+[400-{100-0}]
=-1000+[400-100]
=-1000+300
=-700
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