Question

solve these equation by elimination method​

Answer 1

Answer:

I don't know no no no no no no no no no I don't know no no yenno

Answer 2

$\large\bf\underline\red{Answer \: :-}$

Given :-

• $\sf{ \frac{4}{x} + 3y = 8 }$
• $\sf{ \frac{6}{x} - 4y = - 5}$

To find :-

• x and y

Solution :-

First,

$\rightarrow\sf{ \frac{4}{x} + 3y = 8 } \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rightarrow\sf{x + 3y = \frac{8}{4} } \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rightarrow\sf{x + 3y = 2} \: \: \: \: ...(1)$

Second,

$\rightarrow\sf{ \frac{6}{x} - 4y = - 5 } \: \: \: \: \: \: \: \: \: \\ \\ \rightarrow\sf{6 - 4y = - 5x} \: \: \: \: \: \: \: \: \\ \\ \rightarrow\sf{5x + 4y = 6} \: \: \: ...(2)$

Multiplying equation (1) by 5

We get,

5x + 15y = 10 ...(3)

Subtract equation (2) from (3)

$\longmapsto\sf{5x + 15y - ( 5x + 4y ) = 10 - 6} \\ \longmapsto\sf{5x + 15y - 5x - 4y = 4} \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \longmapsto\sf{11y = 4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \longmapsto\sf{y = \boxed{ \frac{4}{11} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

y = 4/11 putting in equation (1)

$\longmapsto\sf{x + 3 \bigg( \frac{4}{11} \bigg) = 2 } \\ \\ \longmapsto\sf{x + \frac{12}{33} = 2 } \\ \\ \longmapsto\sf{x = 2 - \frac{33}{12} } \\ \\ \longmapsto\sf{x = \frac{24 - 33}{12} } \\ \\ \longmapsto\sf{ x = \frac{9}{12} } \\ \\ \longmapsto\sf{x = \boxed{ \frac{3}{4}} }$

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