Question

solve these equations by cross multiplication method
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first and right answer will be marked as brainlist

Answer 1

Given Equation is 8x + 5y = 9.

Here a1 = 8, b1 = 5, c1 = -9.    ------- (1)

Given Equation is 3x + 2y = 4

Here a2 = 3, b2 = 2, c2 = -4.

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Cross-multiplication method:

$=> \frac{x}{b1c2 - b2c1} = \frac{y}{c1a2 - c2a1} = \frac{1}{a1b2 - a2b1}$

$=> \frac{x}{(5)(-4) - (2)(-9)} = \frac{y}{(-9)(3) - (-4)(8)} = \frac{1}{(8)(2) - (3)(5)}$

Now,

(i)

$=> \frac{x}{(-20) + 18} = \frac{1}{16 - 15}$

$=> \frac{x}{-2} = \frac{1}{1}$

$=> x = -2$

(ii)

$=> \frac{y}{-27 + 32} = \frac{1}{16 - 15}$

$=> \frac{y}{5} = 1$

$=>y = 5$

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Therefore, the values are:

$=> \boxed{x = -2,5}$

Hope this helps!

Answer 2

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