Question

solve these equations....chapter linear equations in one variable....answer as soon as possible....​

Answer 1

Step-by-step explanation:

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Answer 2

(vi)

(p-2/5) /(p+2/5)=5

(5p-2/5) /(5p+2/5)=5 (LCM)

5p-2=5(5p+2)

5p-2=25p+10

25p-5p=-2-10

20p=-12

p=-3/5

(vii)

${x}^{2} - (x + 2 )(x - 2) \div x + 3 = 1 \div 2$

${x }^{2} - {x}^{2} - 4 \div x + 3 = 1 \div 2$

2(-4)=1(x+3)

-8=x+3

x=-11

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