Math, asked by anuragparimal57, 1 year ago

solve these equations only by substitution method--- 2x-3y=13,
7x-2y=20



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Answers

Answered by Anonymous
7

Answer:

x = + 2

y = - 3

Step-by-step explanation:

Given equations are :

2x - 3y = 13 __(A)

7x - 2y = 20 __(B)

Now, we can write eq. (A) as

2x = 13 + 3y

x = \dfrac{13\:+\:3y}{2} __(1)

Put value of x in eq. (B)

\implies 7 (\dfrac{13 \:  +  \: 3y}{2} ) - 2y = 20

\implies ( \dfrac{91 \:  +  \: 21y}{2} ) - 2y = 20

\implies ( \dfrac{91 \:  +  \: 21y \: - 4y}{2} )= 20

\implies ( \dfrac{91 \:  +  \: 17y}{2} ) = 20

\implies 91 + 17y = 20 × 2

\implies 91 + 17y = 40

\implies 17y = 40 - 91

\implies 17y = - 51

  • \boxed{\bold{y \: = \:- 3 }}

Put value of y in eq. (1)

\implies x = \dfrac{13\:+\:3(-3)}{2}

\implies x = \dfrac{13\:-\:9}{2}

\implies x = \dfrac{4}{2}

  • \boxed{\bold{x \:=\: + 2}}

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