Solve these equations PLEASE!!!!!!!
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Answered by
1
Answer:
solution of 3
In no solution,
A1/A2 =B1/B2 not equal to C1/Ç2
therefore,
A1/A2 = B1/B2
k/12 =3/k
( k)(k)=(12)(3)
k^2=36
root on both the sides,which gives us,
k=6
for the value of k=6,we get,
A1/A2 ,B1/B2 ,C1/C2
k/12 3/k k-2/k
6/12 3/6 6-2/6
1/2 1/2 4/6
2/3
here,A1/À2=B1/B2 not equal to C1/C2
Answered by
1
Answer:
hi jaan how are you
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