Question

Solve these following quadratic equations by using the quadratic formula (SRIDHAR ACHARYA’S RULE)

2.) 9x^2+7x-2=0.

5.) p^2x^2+(p^2-q^2)x-q^2=0; p is not equal to 0.

6.)x-1/x-2+x-3/x-4=3 1/3,x is not equal to 2,4.

7.) 1/x-1/x-2=3,x is not equal to 0.

8.) x+1/x=3, x is not equal to 0.

Answer 1

Question:-

$ii) \: \bf{ 9{x}^{2} +7 x - 2 = 0} \\ \huge\bf{Solution}\\ \\ \red{\bf{ shri \: dharacharya \: rule}} \\ \\ \bf{x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \: \: \: , \: \: \: \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} }\\ \\ \bf{here \: \: a = 9 \: , \: \: b = 7 ,\: \: c = - 2} \\ \\ \bf{ x = \frac{ - 7 + \sqrt{49 - ( - 72)} }{2 \times 9} \: ,\: \frac{ - 7 - \sqrt{49 - ( - 72)} }{2 \times 9} } \\ \\ \bf{ x = \frac{ - 7 + \sqrt{121} }{18} \: , \: \frac{ - 7 - \sqrt{121} }{18} } \\ \\ \bf{x = \frac{ - 7 + 11}{18} \:, \: \frac{ - 7 - 11}{18} } \\ \\ \bf{x = \frac{4}{18} \: , \: \frac{ - 18}{18} } \\ \\ \bf{ x = \frac{2}{9} \: , \: - 1}$

Answer 2

Step-by-step explanation:

remaining two questions, try by yourself lol.

thanks